445. Add Two Numbers II

You are given two non-empty linked lists representing two non-negative integers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

You may assume the two numbers do not contain any leading zero, except the number 0 itself.

Follow up:
What if you cannot modify the input lists? In other words, reversing the lists is not allowed.

Example:

Input: (7 -> 2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 8 -> 0 -> 7
class Solution {
public:
    ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
        int n1 = getLength(l1), n2 = getLength(l2), diff = abs(n1 - n2);
        if (n1 < n2) swap(l1, l2);
          ListNode *dummy = new ListNode(0), *cur = dummy, *right = cur;
         while (diff > 0) {
            cur->next = new ListNode(l1->val);
            if (l1->val != 9) right = cur->next;
            cur = cur->next;
            l1 = l1->next;
            --diff;
        }
        while (l1) {
            int val = l1->val + l2->val;
            if (val > 9) {
                val %= 10;
                ++right->val;
                while (right->next) {
                    right->next->val = 0;
                    right = right->next;
                }
                right = cur;
            }
            cur->next = new ListNode(val);
            if (val != 9) right = cur->next;
            cur = cur->next;
            l1 = l1->next;
            l2 = l2->next;
        }
        return (dummy->val == 1) ? dummy : dummy->next;
    }
    int getLength(ListNode* head) {
        int cnt = 0;
        while (head) {
            ++cnt;
            head = head->next;
        }
        return cnt;
    }
};

Reference: https://aaronice.gitbooks.io/lintcode/content/linked_list/add_two_numbers_ii.html
http://www.cnblogs.com/grandyang/p/6216480.html

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